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数学解答题目1.log2(4^7*2^5)+log26-log2

2007-11-10 17:12:10独***
1.log2(4^7*2^5)+log2 6-log2 3 (解释:log2 6是以2为底6的对数,4^7*2^5是4的七次方乘以2的5次方) 请您写下步骤,谢谢您!数学解答题目1.log2(4^7*2^5)+log26-log23(解释:log26是以2为底6的对数,4^7*2^5是4的七次方乘以2的5次方)请您写下步骤,?

最佳回答

  • 　log2(4^7*2^5) + log2 6 - log2 3 = log2(2^19) + log2(6/3) = 19 + log2(2) = 19 + 1 = 20
    2007-11-10 17:18:32
  • (为手机方便表达,将对数的底数放在括号里)。log(2) 4^7×2^5+log(2) 6-log(2) 3=[log(2) 2^14+log(2) 2^5]+[log(2) 2+log(2) 3]-log(2) 3=(14+5)log(2) 2+log(2) 2+log(2) 3-log(2) 3=20log(2) 2=20。
    2007-11-10 19:21:46
  • log2(4^7*2^5)+log2 6-log2 3 =log2(4^7）+log2（2^5)+log2 2+log2 3-log2 3 =log2(2^14）+5+1 =14+5+1 =20
    2007-11-10 17:15:58
    • 很赞哦！ (58)

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