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(tan10°-√3)*cos10°/sin50°=?

2009-08-02 15:27:35←***
(tan10°-√3)*cos10°/sin50°=?:解:(tan10°-√3)×cos10°/sin50° =(sin10°/cos10°-√3)×c?

最佳回答

  • 解:(tan10°-√3)×cos10°/sin50° =(sin10°/cos10°-√3)×cos10°/sin50° =(sin10°-√3cos10°)/sin50° =2(cos60°sin10°-sin60°cos10°)/sin50° =2×sin(10°-60°)/sin50° =-2
    2009-08-02 15:43:44
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