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数学一小题求值sin50度*(1+根号3*tan10度)tenk

2008-03-03 19:40:27d***
求值 sin50度*(1+根号3*tan10度) tenkyu~~~数学一小题求值sin50度*(1+根号3*tan10度)tenkyu~~~:解:我省略“°” sin50(1+√3tan10) =sin50(cos10+√?

最佳回答

  • 解:我省略“°” sin50(1+√3tan10) =sin50(cos10+√3sin10)/cos10 =2sin50[(1/2)cos10+(√3/2)sin10]/cos10 =2sin50(sin30cos10+cos30sin10)/cos10 =2sin50sin40/cos10 =2cos40sin40/cos10 =sin80/cos10 =1
    2008-03-03 19:59:05
  • 很赞哦! (63)