百科知识

教育/科学

分解因式(1)x2+xy-6y2+x+13y-6(2)(x+3)

2006-12-21 22:22:40大***
(1) x2+xy-6y2+x+13y-6 (2) (x+3)(x-5)(x+6)(x-10)-20x2 x2代表x的平方分解因式(1)x2+xy-6y2+x+13y-6(2)(x+3)(x-5)(x+6)(x-10)-20x2x2代表x的平方：(1)解:原式=x^2+xy+x-6?

最佳回答

  • (1)解:原式=x^2+xy+x-6y^2+13y-6 =x^2+x(y+1)-(6y^2-13y+6) =x^2+x(y+1)-(2y-3)(3y-2) =[x-(2y-3)]*[x+(3y-2)] =(x-2y+3)(x+3y-2) (2)解:原式=(x+3)(x-10)(x-5)(x+6)-20x^2 =(x^2-7x-30)(x^2+x-30)-20x^2 令x^2-30=t 则原式=(t-7x)(t+x)-20x^2 =t^2-6tx-27x^2 =(t+3x)(t-9x) 即原式=(x^2+3x-30)(x^2-9x+30)
    2006-12-21 22:51:28
  • (1)解:原式=x^2+xy+x-6y^2+13y-6 =x^2+x(y+1)-(6y^2-13y+6) =x^2+x(y+1)-(2y-3)(3y-2) =[x-(2y-3)]*[x+(3y-2)] =(x-2y+3)(x+3y-2) (2)解:原式=(x+3)(x-5)(x+6)(x-10)-20x^2=(x^2-30-7x)(x^2-30+x)-20x^2=(x^2-30)^2-6x(x^2-30)-27x^2=[(x^2-30)+3x][(x^2-30)-9x]=（x^2+3x-30)(x^2-9x-30)
    2006-12-21 22:59:35
  • (1) x^2+xy-6y^2+x+13y-6=(x+2y+3)(x-3y-2) (2) (x+3)(x-5)(x+6)(x-10)-20x^2=(x^2-30-7x)(x^2-30+x)-20x^2 =(x^2-30)^2-6x(x^2-30)-27x^2=[(x^2-30)+3x][(x^2-30)-9x]
    2006-12-21 22:45:28
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