教育/科学

求不定积分∫dx/(sinxcosx)

2007-11-29 20:35:13赢***

∫dx/(sinxcosx)求不定积分∫dx/(sinxcosx)：∫dx/(sinxcosx) =∫[dx/(cosx)^2]/(sinx/cosx) =∫dtanx/tanx =?

∫dx/(sinxcosx) =∫[dx/(cosx)^2]/(sinx/cosx) =∫dtanx/tanx =lntanx+C.

2007-11-29 21:25:58

很赞哦！ (124)