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不等式x²-3x+2/x²+2x-3≤0的解?

2010-10-05 17:51:49圆***
不等式x²-3x+2/x²+2x_3≤0的解集为?不等式x²-3x+2/x²+2x_3≤0的解集为?:(x²-3x+2)/(x²+2x-3)≤0 解:x²+2?

最佳回答

  • (x²-3x+2)/(x²+2x-3)≤0 解:x²+2x-3≠0 (x-1)(x+3)≠0 x1≠1,x2≠-3 当:x²-3x+2≥0时,x²+2x-30 解得:12010-10-05 18:21:41
  • (x²-3x+2)/(x²+2x-3)≤0 化为{x≠1, {(x-2)/(x+3)<=0, ∴{x≠1, {-32010-10-05 18:42:41
  • 很赞哦! (259)