问题已知-π/2<=α<β<=π/2,则α+
2013-06-05 11:32:10圆***
已知-π/2<=α<β<=π/2,则[α+β]/2的取值范围为问题已知-π/2=αβ=π/2,则[α+β]/2的取值范围为:α、β∈[-π/2,π/2],且α<β.
∴-π/2≤α≤π/2,-π/2?
最佳回答
2013-06-05 13:38:03
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