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数学，详细解答，谢谢（1/3+1/6+1/12+1/24+1/4

2007-09-18 13:47:11小***
（1/3+1/6+1/12+1/24+1/48+1/96+1/192+1/384）×128数学，详细解答，谢谢（1/3+1/6+1/12+1/24+1/48+1/96+1/192+1/384）×128：（1/3+1/6+1/12+1/24+1/48+?

最佳回答

  • （1/3+1/6+1/12+1/24+1/48+1/96+1/192+1/384）×128 =(1/3+1/6+1/12+1/24+1/48+1/96+1/192+1/384+1/384-1/384)*128 =(2/3-1/384)*128 =255/3=85
    2007-09-18 14:17:31
  • 设M=1/3+1/6+1/12+1/24+1/48+1/96+1/192+1/384。。。第一式 式子两边同乘2得 2M=2/3+1/3+1/6+1/12+1/24+1/48+1/96+1/192。。。。。第二式 第二式等式两边同时减去第一式等式两边得 M=2/3-1/384=255/384=85/128 则原式=M*128=（85/128）*128=85
    2007-09-18 16:53:45
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