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已知函数f(x)=(k+1)/x(k<0),求使得f(x+?

2008-06-29 18:29:23b***
已知函数f(x)=(k+1)/x(k<0),求使得f(x+k)>1成立的x的集合已知函数f(x)=(k+1)/x(k0),求使得f(x+k)1成立的x的集合:f(x)=(k+1)/x,(k1 ---?

最佳回答

  • f(x)=(k+1)/x,(k1 --->(k+1)/(x+k)>1 --->1-(k+1)/(x+k)(x-1)/(x+k)1(k<-1)时,12008-06-29 18:48:42
  • 解: f(x+k)=(k+1)/(x+k)>1 [(k+1)/(x+k)]-1>0 [(k+1)/(x+k)]-(x+k)/(x+k)>0 (x-1)/(x+k)1时 ,k-1 k<0(题意) -12008-06-29 18:46:16
  • (K+1)/(X+K)>1 (K+1-X-K)/(X+K)>0 (X-1)(X+K)-1 -K2008-06-29 18:37:24
  • 很赞哦! (67)