三角恒等tan^2@=sin^2@/(1-sin^2@),怎样才
2010-01-04 10:11:331***
tan^2@=sin^2@/(1-sin^2@),怎样才能使sin^2@=tan^2/(1+tan^2@)三角恒等tan^2@=sin^2@/(1-sin^2@),怎样才能使sin^2@=tan^2/(1+tan^2@):怎样才能使tan^2@=sin^2@/(1-?
最佳回答
2010-01-04 12:53:59
2010-01-04 11:23:02
很赞哦! (96)