百科知识

高一数学化简sinA分之sin(2A+B)-2cos(A+B)

2008-04-04 22:51:03a***
sinA分之sin(2A+B)-2cos(A+B)高一数学化简sinA分之sin(2A+B)-2cos(A+B):sin(2A+B)/sinA-2cos(A+B) =【sinAcos(A+B)+cosAsin?

最佳回答

  • sin(2A+B)/sinA-2cos(A+B) =【sinAcos(A+B)+cosAsin(A+B)】/sinA-2cos(A+B) =cos(A+B)+cosAsin(A+B)/sinA-2cos(A+B) =cosAsin(A+B)/sinA-cos(A+B) =【cosAsin(A+B)-sinAcoa(A+B)】/sinA =-【sinAcoa(A+B)-cosAsin(A+B) 】/sinA =-sin(A-A-B)/sinA =sinB/sinA
    2008-04-04 23:30:13
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