(2)请大家来帮我看看,急明天要交.(麻烦大家给出详细过程)这是
2007-05-21 21:30:12s***
这是一道化简题目: x/x-2 + x/x^2+2x - x+6/x^2-4(2)请大家来帮我看看,急明天要交.(麻烦大家给出详细过程)这是一道化简题目:x/x-2+x/x^2+2x-x+6/x^2-4：原式=x/x+2 + x/x?
最佳回答
原式=x/x+2 + x/x(x+2) - x+6/(x+2)(x-2)
=x/x+2 + 1/(x+2) - x+6/(x+2)(x-2)
=x(x-2)/(x+2)(x-2) + x-2/(x+2)(x-2) - x+6/(x+2)(x-2)
=x^2-2x-8/(x+2)(x-2)
=(x-4)(x+2)/(x+2)(x-2)
=x-4/x-2
2007-05-21 21:39:08
x x x+6
原式= ----- + -------- - ----------
x-2 x(x+2) (x+2)(x-2)
x 1 x+6
= ----- + ----- - ------------
x-2 x+2 (x+2)(x-2)
x(x+2)+x-2 -(x+6)
= --------------------
(x+2)(x-2)
x^2+2x-8
= ----------
(x+2)(x-2)
(x-2)(x+4)
= ----------
(x+2)(x-2)
x+4
= -------
x+2
。
2007-05-21 22:23:37
x/(x-2) + x/(x^2+2x) - (x+6)/(x^2-4)
=x/(x-2)+x/[x(x+2)]-(x+6)/[(x-2)(x+2)]
=x/(x-2)+1/(x+2)-(x+6)/[(x-2)(x+2)]
=x(x+2)/[(x-2)(x+2)]+(x-2)/[(x-2)(x+2)]-(x+6)/[(x-2)(x+2)]
=[x(x+2)+(x-2)-(x+6)]/[(x-2)(x+2)]
=(x^+2x+x-2-x-6)/[(x-2)(x+2)]
=(x^+2x-8)/[(x-2)(x+2)]
=[(x-2)(x+4)]/[(x-2)(x+2)]
=(x+4)/(x+2)
2007-05-21 22:04:15
能否具体点啊,看不清楚哦
x/x-2 + x/x^2+2x - x+6/x^2-4
= x/(x-2)+x/x(x+2)-(x+6)/(x-2)(x+2)
=x(x+2)/(x-2)(x+2)+(x-2)/(x-2)(x+2)-(x+6)/(x-2)(x+2)
=(x^2+2x+4)/(x^2-4)
2007-05-21 21:36:49
很赞哦！ (92)
