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帮忙求隐函数的导数题目见浏览

2007-12-08 15:58:39不***
题目见浏览帮忙求隐函数的导数题目见浏览：(1)3y^2y'+3x^2-3(y+xy')=0, (y^2-x)y'+(x^2-y)=0 y'=-(x^2-y)/(y^2-?

最佳回答

  • (1)3y^2y'+3x^2-3(y+xy')=0, (y^2-x)y'+(x^2-y)=0 y'=-(x^2-y)/(y^2-x) (2)(1/[1+(y/x)^2)])*[(xy'-y)/x^2]=(1/2)[1/(x^2+y^2)](2x+2yy') xy'-y=x+yy', (x-y)y'=x+y y'=(x+y)/(x-y)
    2007-12-08 17:33:25
    • 很赞哦！ (198)

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