一道数学题已知实数a、b满足条件-a-b-=b/a<1,化
2006-01-29 08:48:26f***
已知实数a、b满足条件|a-b|=b/a<1,化简代数式(1/a-1/b)√(a-b-1)^2,将结果表示成只含有字母a的形式。
一道数学题已知实数a、b满足条件|a-b|=b/a1,化简代数式(1/a-1/b)√(a-b-1)^2,将结果表示成只含有字母a的形式。:∵|a-b|=?
最佳回答
∵|a-b|=b/ab,
∴ a-b=b/a, a^2-ab=b, 解得b=a^2/(a+1)
∴(1/a-1/b)√(a-b-1)^2=(b-a)/ab *(1-b/a)=-1/a^2*(a-b)/a=)=(-1/a^2)*(b/a^2)=-1/a^2(a+1)
若a、b同为负数,由b/aa,
∴ a-b=-b/a, a^2-ab=-b, 解得b=a^2/(a-1)
∴(1/a-1/b)√(a-b-1)^2=(b-a)/ab *(1+b/a)=(b/a)/ab*(a+b)/a=(a+b)/a^3=(a+a^2/(a-1))/a^3=(2a-1)/a^2(a-1)
2006-01-29 10:24:27
|a-b|-1 此时 (1/a-1/b)√(a-b-1)^2 = -1/b = -(a+1)/a^2
01 此时 (1/a-1/b)√(a-b-1)^2 = -1/b = (a-1)/a^4
2006-01-30 08:18:50
|a-b|-1 (1/a-1/b)√(a-b-1)^2 = -1/b = -(a+1)/a^2
当01 (1/a-1/b)√(a-b-1)^2 = -1/b = (a-1)/a^4
2006-01-29 23:51:28
解法不一样!
2006-01-29 20:21:27
∵|a-b|=b/ab,
∴ a-b=b/a, a^2-ab=b, 解得b=a^2/(a+1)
∴(1/a-1/b)√(a-b-1)^2=(b-a)/ab *(1-b/a)=-1/a^2*(a-b)/a=)=(-1/a^2)*(b/a^2)=-1/a^2(a+1)
若a、b同为负数,由b/aa,
∴ a-b=-b/a, a^2-ab=-b, 解得b=a^2/(a-1)
∴(1/a-1/b)√(a-b-1)^2=(b-a)/ab *(1+b/a)=(b/a)/ab*(a+b)/a=(a+b)/a^3=(a+a^2/(a-1))/a^3=(2a-1)/a^2(a-1)
2006-01-29 16:47:47
a-b|-1 此时 (1/a-1/b)√(a-b-1)^2 = -1/b = -(a+1)/a^2
01 此时 (1/a-1/b)√(a-b-1)^2 = -1/b = (a-1)/a^4
对于解法的不同而不同.
2006-01-29 15:34:08
|a-b|-1 此时 (1/a-1/b)√(a-b-1)^2 = -1/b = -(a+1)/a^2
01 此时 (1/a-1/b)√(a-b-1)^2 = -1/b = (a-1)/a^4
2006-01-29 13:24:46
a-b|-1 此时 (1/a-1/b)√(a-b-1)^2 = -1/b = -(a+1)/a^2
01 此时 (1/a-1/b)√(a-b-1)^2 = -1/b = (a-1)/a^4
2006-01-29 13:08:40
a-b|-1 此时 (1/a-1/b)√(a-b-1)^2 = -1/b = -(a+1)/a^2
01 此时 (1/a-1/b)√(a-b-1)^2 = -1/b = (a-1)/a^4
2006-01-29 11:23:25
|a-b|-1 此时 (1/a-1/b)√(a-b-1)^2 = -1/b = -(a+1)/a^2
01 此时 (1/a-1/b)√(a-b-1)^2 = -1/b = (a-1)/a^4
2006-01-29 11:17:21
对于解法的不同而不同.
2006-01-29 11:12:27
a-b|-1 此时 (1/a-1/b)√(a-b-1)^2 = -1/b = -(a+1)/a^2
01 此时 (1/a-1/b)√(a-b-1)^2 = -1/b = (a-1)/a^4
2006-01-29 09:38:04
|a-b|-1 此时 (1/a-1/b)√(a-b-1)^2 = -1/b = -(a+1)/a^2
01 此时 (1/a-1/b)√(a-b-1)^2 = -1/b = (a-1)/a^4
2006-01-29 09:20:04
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